If 3 men can paint a box in 2 days, what part of the job can be completed by 2 men in 1 day?

Logic and methodology would be appreciated.If 3 men can paint a box in 2 days, what part of the job can be completed by 2 men in 1 day?
You need to figure out how much of the job a man does in a day.





3 men take 2 days to finish a job. So 1 man would take 6 days. Stated another way, a man finishes 1/6 of the job each day.





If you have 2 men, then they would finish 2 * 1/6 = 1/3 of the job in a day.





The answer is 1/3 of the box.If 3 men can paint a box in 2 days, what part of the job can be completed by 2 men in 1 day?
3 men will take 2 days


--%26gt; 3 men = 2 days





1 man will take 3 times as long


--%26gt; 1 man = 2 x 3 days = 6 days





2 men will take half the time as 1 man


--%26gt; 2 men = 6 / 2 days = 3 days





2 men will take 3 days to paint the box. Therefore, considering they do the work at an even pace, after one day they would have completed one third (1/3) of the box.
one-thirds
3men, 2days= a job


3 men, 1 day = half a job鈥?


2 men, 1 day = 2 quarters(2/3) of a job of the half of a day


so overall, it would be...0.3333% or else 1/3
3 men * 2 days = six panels


3 * 2 = 6


6 = 6


1 man = 1 panel





(2 men/panels * 1 day) * X = six panels


2 panels * X = six panels





the answer is 1/3; do you see how I found it?
a third would be a reasonable answer.











3 men for two days = 6 man days.


2 men for one days = 2 man days.








6 mandays = 1 complete box


2 mandays = 1/3 of a box